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### Answers (1)

Order=2, Degree=2 , Non- linear

Hint:

The order is the highest numbered derivative in the equation with no negative or fractional power of the dependent variable and its derivatives, while the degree is the highest power to which a derivative is raised.

Given:
$\left ( {y}'' \right )^{2}+\left ( {y}' \right )^{3}+\sin y=0$

Solution:

Concept of the question

$\sin x=x-\frac{x^{3}}{3!}+\frac{x^{5}}{5!}-\frac{x^{7}}{7!}+......+\left ( \frac{(-1)^{r}x^{2x+1}}{\left ( 2r+1 \right )!} \right )$

So in this question,  x of $\sin x$ is replaced by y which means that the power of y is not defined as it approaches to infinity by the above formula.

Here in this question, the order of the differential equation is 2 and the degree of the differential equation is not defined.

In a differential equation, when the dependent variable and their derivatives are only multiplied by constant or independent variable, then the equation is linear.

Here the dependent variable is y and the term y is multiplied by itself. So this equation is non-linear differential equation.

Therefore, Order=2, Degree=2, Non- linear

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