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Explain solution RD Sharma class 12 chapter Differential Equation exercise 21.2 question 3 subquestion (ii) maths

Answers (1)

Answer:

 \left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{3}+2\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+x \frac{\mathrm{d} y}{\mathrm{d} x}-y=0

Hint:

 Differentiating the given curve, c- Parameter

Given:

 y=cx+2c^{2}+c^{3}

Solution:

y=cx+2c^{2}+c^{3}

\begin{aligned} &\frac{\mathrm{d} y}{\mathrm{d} x}=c+0 \\ &c=\frac{\mathrm{d} y}{\mathrm{d} x} \\ &y=x\frac{\mathrm{d} y}{\mathrm{d} x}+2\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{3} \end{aligned}

\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{3}+2\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+x \frac{\mathrm{d} y}{\mathrm{d} x}-y=0

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Gurleen Kaur

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