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  • Explain solution RD Sharma class 12 chapter 21 diffrential equations excercise 21.4 Question 1

Explain solution RD Sharma class 12 chapter 21 diffrential equations excercise 21.4 Question 1

Answers (1)

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Answer:  y=\log x is the solution of given function.

Hint:

Just differentiate the function & then put value

Given:

y=\log x is the function.

Solution:

Differentiate with respect to  x

\begin{aligned} &\Rightarrow \frac{d y}{d x}=\frac{d}{d x}(\log x) \\ &\Rightarrow \frac{d y}{d x}=\frac{1}{x} \\ &\Rightarrow x \frac{d y}{d x}=1 \end{aligned}

Hence the function satisfies the equation.

Also, when 

\begin{aligned} &x=1 \\ &y=\log 1=0 \end{aligned}

Thus  y(1)=0 satisfies the initial value problem.

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