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Provide solution for RD Sharma maths class 12 chapter 21 Differential Equation exercise Fill in the blank question 6

Answers (1)

Answer:

 e^{y}=e^{x}+c

Hint:

 First use the variable separation method then integrating both sides.

Given:

 \frac{\mathrm{d} y}{\mathrm{d} x}=e^{x-y}

Solution:

\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{e^{x}}{e^{y}}

\Rightarrow \int e^{y}dy=\int e^{x}dy

\Rightarrow e^{y}=e^{x}+c

So, the answer is

e^{y}=e^{x}+c

Posted by

Gurleen Kaur

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