Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter Differential Equations exercise 21.7 question 14

Provide solution for RD Sharma maths class 12 chapter Differential Equations exercise 21.7 question 14

Answers (1)

Answer: \sin y=e^{x} \log x+c

Hint: Separate the terms of x and y and then integrate them.

Given: \frac{d y}{d x}=\frac{x e^{x} \log x+e^{x}}{x \cos y}

Solution: \frac{d y}{d x}=\frac{x e^{x} \log x+e^{x}}{x \cos y}

         \cos y d y=\frac{x \cdot e^{x} \log x+e^{x}}{x} d x

          Integrating both sides

        \begin{aligned} &\int \cos y d y=\int e^{x} \log x d x+\int \frac{e^{x}}{x} d x \\\\ &\sin y=\log x \int e^{x} d x-\int \frac{1}{x}\left(\int e^{x} d x\right) d x+\int \frac{e^{x}}{x} d x \end{aligned}

        \begin{aligned} &\sin y=e^{x} \log x-\int \frac{e^{x}}{x} d x+\int \frac{e^{x}}{x} d x+c \\\\ &\sin y=e^{x} \log x+c \end{aligned}

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

When will CBSE Class 12 results 2025 be declared? Last two years' trends
anam-khan

CBSE Class 10, 12 board exams 2025 from April 7 to 11 for sports students
anam-khan

CBSE Class 12 history paper 2025 moderately difficult, tested students’ understanding

Latest Question