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Provide solution for RD Sharma maths class 12 chapter Differential Equation exercise 21.3 question 10

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Answer:

y=a x^{3}+b x^{2}+c  is a solution

Hint:

Differentiate the given solution.

Given:

y=a x^{3}+b x^{2}+c


Solution:

Differentiating on both sides with respect to x

\begin{aligned} &\frac{d y}{d x}=\frac{d}{d x}\left(a x^{3}+b x^{2}+c\right) \\\\ &\frac{d y}{d x}=3 a x^{2}+2 b x+0 \\\\ &\frac{d y}{d x}=3 a x^{2}+2 b x \end{aligned}        .................(i)

Differentiate equation (i) with respect to x,

\begin{aligned} &\frac{d^{2} y}{d x^{2}}=\frac{d}{d x}\left(3 a x^{2}+2 b x\right) \\\\ &\frac{d^{2} y}{d x^{2}}=6 a x+2 b \end{aligned}                ..............(ii)

Differentiate equation (ii) with respect to x,

\frac{d^{3} y}{d x^{3}}=6 a

Thus, y=a x^{3}+b x^{2}+c  is a solution of differential equation.

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