Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve R.D.Sharma class 12 Chapter 21 Differential Equations Exercise Revision Exercise Question 21 Maths textbook Solution.

Please Solve R.D.Sharma class 12 Chapter 21  Differential Equations Exercise Revision Exercise Question 21 Maths textbook Solution.

Answers (1)

Answer:y+2x^{2}=e^{x}+c

Hint: Apply integration to find the equation

Given:  \frac{dy}{dx}+4x=e^{x}

Solution:  \frac{dy}{dx}+4x=e^{x}

              \begin{aligned} &\Rightarrow \frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{e}^{\mathrm{x}}-4 \mathrm{x} \\ &\Rightarrow \mathrm{dy}=\left(\mathrm{e}^{\mathrm{x}}-4 \mathrm{x}\right) \mathrm{dx} \end{aligned}

             integrate both sides

             \begin{aligned} &\Rightarrow \int d y=\int\left(e^{x}-4 x\right) d x \\ &\Rightarrow \quad y=e^{x}-4 * \frac{x^{2}}{2}+c \\ &\Rightarrow \quad y=e^{x}-2 * x^{2}+c \\ &\Rightarrow \quad y+2 x^{2}=e^{x}+c \end{aligned}

 

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE addresses Class 12 post-result glitches, promises refund for extra fee charged
anam-khan

CBSE extends deadline to obtain Class 12 scanned copies till May 24
anam-khan

‘Stop defending your so-called flawless OSM’: Class 12 students slam CBSE over blurred answer sheets

Latest Question