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Need solution for RD Sharma maths class 12 chapter Differential Equation exercise 21.2 question 3 subquestion (i)

Answers (1)

Answer:

 2x(\frac{\mathrm{d} y}{\mathrm{d} x})=y

Hint:

 Differentiating the given equation with respect to x

Given:

 y^{2}=4ax

Solution:

y^{2}=4ax

a=\frac{y^{2}}{4x}

On differentiating with respect to x,

2y\frac{\mathrm{d} y}{\mathrm{d} x}=4a

Substituting the value of a, we get

\begin{aligned} &2y\frac{\mathrm{d} y}{\mathrm{d} x}=4\frac{y^{2}}{4x} \\ &2y\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{y^{2}}{x} \\ &2x(\frac{\mathrm{d} y}{\mathrm{d} x})=y \end{aligned}

Hence,

\begin{aligned} &2x(\frac{\mathrm{d} y}{\mathrm{d} x})=y \end{aligned}

is the differential equation corresponding to y^{2}=4ax

Posted by

Gurleen Kaur

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