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Need solution for  RD Sharma maths Class 12 Chapter 21 Differential Equation Exercise Multiple Choice Question Question 11 textbook solution.

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Answer : \text { (a) } y=\frac{1}{x^{2}}

Hint: Use variable separable method i.e. take the y terms in one side and x terms in the other.

Given : \frac{d y}{d x}+\frac{2 y}{x}=0

Explanation : \frac{d y}{d x}=-\frac{2 y}{x}

\begin{aligned} &\frac{d y}{y}=-2 \frac{d x}{x} \\ &\log y=-2 \log x+\log C \\ &y=\frac{C}{x^{2}} \end{aligned}

\begin{aligned} &x^{2} y=C \\ &\text { Given, } y(1)=1 \\ &y=\frac{c}{1}=1 \end{aligned}

Hence,

\begin{aligned} &x^{2} y=1 \\ &y=\frac{1}{x^{2}} \end{aligned}

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