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  • Provide solution for RD Sharma maths class 12 chapter 21 Differential Equation exercise Fill in the blank question 26

Provide solution for RD Sharma maths class 12 chapter 21 Differential Equation exercise Fill in the blank question 26

Answers (1)

Answer:

 Degree=4

Hint:

 Degree = Highest power of the highest order derivative.

Given:

 The degree of differential equation

y=x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+\left ( \frac{\mathrm{d} x}{\mathrm{d} y} \right )^{2}

is _______

Solution:

y=x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+\left ( \frac{\mathrm{d} x}{\mathrm{d} y} \right )^{2}

y=x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{-2}

y=x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}+\frac{1}{\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}}

y=\frac{x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{4}+1}{\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}}

y\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}=x\left ( \frac{\mathrm{d} y}{\mathrm{d} x} \right )^{4}+1

So, the degree of above differential equation is 4

Posted by

Gurleen Kaur

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