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Provide solution for RD Sharma maths class 12 chapter 21 Differential Equation exercise Fill in the blank question 18

Answers (1)

Answer:

 x=C\, sec\, y

Hint:

 Integrating both sides

Given:

 cot \, y\, dx=x\, dy

Solution:

cot \, y\, dx=x\, dy

Separate the variable and integrating both sides, we get

\begin{aligned} &\int \frac{1}{x}dx=\int tan\, y\, dy \end{aligned}

\begin{aligned} &\Rightarrow log\, x=log\left | sec\, y \right |+log\, C \\ &\Rightarrow log\frac{x}{sec\, y}=log \, C \\ &\Rightarrow \frac{x}{sec\, y}= C \\ &\Rightarrow x=C\, sec\, y \end{aligned}

So, the answer is C sec y

Posted by

Gurleen Kaur

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