Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Differential Equation exercise 21.2 question 13 maths

Explain solution RD Sharma class 12 chapter Differential Equation exercise 21.2 question 13 maths

Answers (1)

Answer:

 \frac{\mathrm{d} y}{\mathrm{d} x}+2xy=4x^{3}

Hint:

 \begin{aligned} &y=2(x^{2}-1)+ce^{-x^{2}} \\ &y=2x^{2}-2+ce^{-x^{2}} \\ &2x^{2}-y=2-ce^{-x^{2}} \\ &\text { Substitutes } 2-ce^{-x^{2}} \text { by } 2x^{2}-y \end{aligned}

Given:

 \begin{aligned} &\frac{\mathrm{d} y}{\mathrm{d} x}=4x+ce^{-x^{2}}(-2x) \\ &\frac{\mathrm{d} y}{\mathrm{d} x}=2x(2-ce^{-x^{2}}) \\ &\frac{\mathrm{d} y}{\mathrm{d} x}=2x(2x^{2}-y) \\ &\frac{\mathrm{d} y}{\mathrm{d} x}=4x^{3}-2xy \\ &\frac{\mathrm{d} y}{\mathrm{d} x}+2xy=4x^{3} \end{aligned}

Hence proved.

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question