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  • Need solution for RD Sharma maths class 12 chapter Differential Equation exercise 21.2 question 15 subquestion (ii)

Need solution for RD Sharma maths class 12 chapter Differential Equation exercise 21.2 question 15 subquestion (ii)

Answers (1)

Answer:

 2xy\frac{dy}{dx}-(y^{2}+4x^{2})=0

Hint:

 Differentiating the given equation

Given:

 (2x-a)^{2}-y^{2}=a^{2}

Solution:

\begin{aligned} &2(2x-a)2-2y\frac{\mathrm{d} y}{\mathrm{d} x}=0\\ &2x-a=\frac{y}{2}\frac{\mathrm{d} y}{\mathrm{d} x}\\ &a=\left ( 2x-\frac{x}{2}\frac{\mathrm{d} y}{\mathrm{d} x} \right )\\ &\left ( \frac{y}{2}.\frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}-y^{2}=4x^{2}+\left ( \frac{y}{2}.\frac{\mathrm{d} y}{\mathrm{d} x} \right )^{2}-2.2a.\frac{y}{2}.\frac{\mathrm{d} y}{\mathrm{d} x} \end{aligned}

2xy\frac{dy}{dx}-(y^{2}+4x^{2})=0

Posted by

Gurleen Kaur

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