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Please solve RD Sharma class 12 chapter Differential Equation exercise 21.2 question 1 maths textbook solution

Answers (1)

Answer:

 8(\frac{\mathrm{dy} }{\mathrm{d} x})^{3}-27y=0

Hint:

 Differentiating the given equation

Given:

 y^{2}=(x-c)^{3}

Solution:

y^{2}=(x-c)^{3}

2y\frac{\mathrm{dy} }{\mathrm{d} x}=3(x-c)^{2}

\sqrt{\frac{2y\frac{\mathrm{dy} }{\mathrm{d} x}}{3}}=(x-c)

y^{2}=(x-c)^{3}=(\frac{2y\frac{\mathrm{dy} }{\mathrm{d} x}}{3})^{\frac{3}{2}}

y^{4}=(\frac{2y\frac{\mathrm{dy} }{\mathrm{d} x}}{3})^{3}

y^{4}=\frac{8y^{3}}{27}(\frac{\mathrm{dy} }{\mathrm{d} x})^{3}

y=\frac{8}{27}(\frac{\mathrm{dy} }{\mathrm{d} x})^{3}

8(\frac{\mathrm{dy} }{\mathrm{d} x})^{3}-27y=0

Posted by

Gurleen Kaur

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