Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 21 Differential Equations Exercise Revision Exercise Question 26 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 21 Differential Equations Exercise Revision Exercise Question 26 Maths Textbook Solution.

Answers (1)

Answer: \sin x\sin y=c

Hint: You must know about trigonometric identities.  

Given:\tan y\; dx+\tan \: x\; dy=0

Solution:\tan y\; dx+\tan \: x\; dy=0

          \begin{aligned} &\Rightarrow \tan x d y=-\tan y d x \\ &\Rightarrow \frac{1}{-\tan y} d y=\frac{1}{\tan x} d x \\ &\Rightarrow \cot y d y=-\cot x d x\left(\because \frac{1}{\tan x}=\cot x\right) \end{aligned}

           Integrating both sides

          \begin{aligned} &\Rightarrow \int \cot y d y=-\int \cot x d x \\ &\Rightarrow \log |\sin y|=-\log |\sin x|+\log c \\ &\Rightarrow \log |\sin y|+\log |\sin x|=\log c \\ &\Rightarrow \log |\sin y \sin x|=\log c(\because \log a+\log b=\log a b) \\ &\Rightarrow \sin y \sin x=c \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12: Delhi Government school teachers ask board to put on-screen marking system on hold
anam-khan

CBSE Board Exam 2026 LIVE: CBSE Class 12 Chemistry ends; question paper analysis, answer key
anam-khan

CBSE Class 12 Geography Paper Analysis: Easy to moderate in difficulty, map-based, MCQ questions manageable

Latest Question