Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 1 maths textbook solution.

Please solve RD Sharma Class 12 Chapter 21 Differential Equation exercise 21.5 question 1 maths textbook solution.

Answers (1)

Answer:  y =\frac{x^3}{3}+\frac{x^2}{2}+-\log \left | x \right |+C

Hint: You have to integrate by applying integration of xn.

Given: \frac{dy}{dx}=x^2+x-\frac{1}{x},x\neq 0

Solution: \frac{dy}{dx}=x^2+x-\frac{1}{x}

dy=\left (x^2+x-\frac{1}{x} \right )dx

Integrating both sides,

\begin{aligned} &\int d y=\int\left(x^{2}+x-\frac{1}{x}\right) d x \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; &\left[\int x^{n} d x=\frac{x^{n+1}}{n+1}+C \& \int \frac{1}{x} d x=\log |x|+C\right]\\ &y=\frac{x^{3}}{3}+\frac{x^{2}}{2}+\log |x|+C \mid \end{aligned}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Latest Question