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Provide solution for RD Sharma maths class 12 chapter Differential Equation exercise 21.2 question 3 subquestion (iv)

Answers (1)

Answer:

 \frac{\mathrm{d}^{3} y}{\mathrm{d} x^{3}}=0

Hint:

 Differentiating the given equation

Given:

 y=ax^{2}+bx+c

Solution:

y=ax^{2}+bx+c

\begin{aligned} &\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{\mathrm{d} }{\mathrm{d} x}(ax^{2}+bx+c) \\ &\frac{\mathrm{d} y}{\mathrm{d} x}=2ax+b \\ &\frac{\mathrm{d}^{2} y}{\mathrm{d} x^{2}}=\frac{\mathrm{d} }{\mathrm{d} x}(2ax+b) \end{aligned}

\begin{aligned} &\frac{\mathrm{d}^{2} y}{\mathrm{d} x^{2}}=2a \\ &\frac{\mathrm{d}^{3} y}{\mathrm{d} x^{3}}=\frac{\mathrm{d} }{\mathrm{d} x}(2a) \\ &\frac{\mathrm{d}^{3} y}{\mathrm{d} x^{3}}=0 \end{aligned}

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Gurleen Kaur

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