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Name: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 4 math
Uploaded: Fri, 2021-08-06 10:42
Description: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 4 math

#CBSE 12 Class
#Maths
#RD Sharma Vol. 1 Class 12
#School
#R.D. Sharma
#Inverse Trigonometric Functions

#1.3
#3.1
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#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 4 math

Answers (1)

Answer: $\pi-2 \tan ^{-1} x$

Given:

$x>1, \sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)$

Hint:

$2 \tan ^{-1} x=\pi-\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right) for x>1$

Solution:

$\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)=\pi-2 \tan ^{-1} x$

Posted by

infoexpert22

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 4 math

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