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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 4 math

Answers (1)

Answer: \pi-2 \tan ^{-1} x

Given:

x>1, \sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)

Hint:

2 \tan ^{-1} x=\pi-\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right) for x>1

Solution:

\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)=\pi-2 \tan ^{-1} x

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