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  • Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.10 Question 2 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.10 Question 2 Maths Textbook Solution

Answers (1)

Answer: \frac{3\pi }{4}
Hint: Check how \sin^{-1}x can be expressed in terms of \cos^{-1}x
Given:\cos^{-1}x+ \cos^{-1}y =\frac{\pi }{4}
Here, we have to compute
\sin^{-1}x+ \sin^{-1}y
Solution:
Let’s replace \sin^{-1}x  by \frac{\pi }{2} - \cos^{-1}x
Now,\sin^{-1}x+ \sin^{-1}y
\! \! \! \! \! \! \! \! \! \! \Rightarrow \frac{\pi }{2} - \cos^{-1}x + \frac{\pi }{2} - \cos^{-1}y\\ = \frac{\pi }{2} + \frac{\pi }{2} - \cos^{-1}x+ \cos^{-1}y\\ = \pi - \frac{\pi }{4}\\ = \frac{3\pi }{4}
Concept: Properties and relations between inverse trigonometric functions.
Note: Remember properties of Trigonometric functions.    

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