Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need Solution for R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonomeric Functions Exercise Multiple Choice Questions Question 5 Maths Textbook Solution.

Need Solution for R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonomeric Functions Exercise Multiple Choice Questions Question 5 Maths Textbook Solution.

Answers (1)

Solution:  Since ,

      \\ \\ \Rightarrow \hspace{1cm} \tan^{-1}x +\cos^{-1}(\frac{y}{\sqrt{1+y^{2}}})=\sin^{-1}(\frac{3}{\sqrt{10}})\\ \\ \Rightarrow \hspace{1cm}\tan^{-1}x+\tan^{-1}(\frac{1}{y})=\tan^{-1}3\\ \\ \Rightarrow \hspace{1cm}\tan^{-1}(\frac{1}{y})=\tan^{-1}3-\tan{-1}x\\ \\ \Rightarrow \hspace{1cm}\tan^{-1}(\frac{1}{y})=\tan^{-1}(\frac{3-x}{1+3x})\\ \\ \Rightarrow \hspace{1cm}y=\frac{1+3x}{3-x}=-3+\frac{10}{3-x}

For positive integer y,x must be 1 and 2 

\\ \\ \therefore \hspace{1cm}y(at\hspace{0.2cm}x=1)=2

and   \\ \\ \hspace{1cm}y(at \hspace{0.2cm}x=2)=7    

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2027 Live: Class 10, 12 timetable soon; LOC submission with late fee till October 30
anam-khan

CBSE Exam Date 2027 Highlights: Class 10, 12 exam dates soon on cbse.gov.in; private candidate form
anam-khan

CBSE 10th, 12th board exam schedule 2027: Sample papers, passing marks

Latest Question