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Name: Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 34
Uploaded: Mon, 2021-07-26 19:07
Description: Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 34

#RD Sharma Vol. 1 Class 12
#Maths
#Inverse Trigonometric Functions
#School
#CBSE 12 Class
#R.D. Sharma

#1.3
#3.1
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 34

Answers (1)

Answer:

$\frac{2\pi}{3}$

Hints:

You must have known about the principal values of inverse functions.

Given:

$\cos^{-1}\left ( -\frac{1}{2}\right )$ is

Solution:

$\cos^{-1}\left ( -\frac{1}{2}\right )=y$

$\cos y=\frac{1}{2}$

$\cos y=\cos\left ( \frac{2\pi}{3} \right )$

Since range of $\cos^{-1}$ is $\left [ 0,\pi \right ]$

Hence, principal value is $\frac{2\pi}{3}$

Posted by

infoexpert27

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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 34

Answers (1)

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