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Name: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 60 math
Uploaded: Sat, 2021-08-07 16:19
Description: Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 60 math

#R.D. Sharma
#RD Sharma Vol. 1 Class 12
#CBSE 12 Class
#Maths
#Inverse Trigonometric Functions
#School

#1.3
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 60 math

Answers (1)

Answer: $\frac{\pi}{8}$

Given

$\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)$

Hint: To solve $\tan$ function we can get the solution.

Solution:

$\begin{aligned} \tan ^{-1}\left(\tan \frac{9 \pi}{8}\right) &=\tan ^{-1}\left(\tan \left(\pi+\frac{\pi}{8}\right)\right) \\ &=\tan ^{-1}\left(\tan \left(\frac{\pi}{8}\right)\right) \\ &=\frac{\pi}{8} \end{aligned}$

Posted by

infoexpert22

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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 60 math

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