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Name: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 42
Uploaded: Fri, 2021-08-06 22:53
Description: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 42

#CBSE 12 Class
#Maths
#RD Sharma Vol. 1 Class 12
#School
#R.D. Sharma
#Inverse Trigonometric Functions

#1.3
#3.1
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#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 42

Answers (1)

Answer: $\frac{11 \pi}{12}$

Given:

$\tan ^{-1} 1+\cos ^{-1}\left(\frac{-1}{2}\right)$

Hint:

Principal range of $\cos (0, \pi)$

Solution:

$\begin{aligned} \tan ^{-1}(1)+\cos ^{-1}\left(-\frac{1}{2}\right) &=\tan ^{-1}\left(\tan \frac{\pi}{4}\right)+\cos ^{-1}\left(\cos \frac{2 \pi}{3}\right) \\ &=\frac{\pi}{4}+\frac{2 \pi}{3} \\ &=\frac{11 \pi}{3} \end{aligned}$

Posted by

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 42

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