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Need solution for RD Sharma maths class 12 chapter 3 Inverse Trigonometric Functions exercise  Very short answer question 63 math

Answers (1)

Answer:  \frac{3 \pi}{4}

Given: \cot ^{-1} 2\ \ and \ \ \cot ^{-1} 3 , then third angle.

Hint: The sum of tree angles of a triangle is \pi

Solution:    

\begin{array}{l} \tan ^{-1} \frac{1}{3}+\tan ^{-1} \frac{1}{2}+\tan ^{-1} x=\pi \\\\ \tan ^{-1} \frac{\left(\frac{1}{3}+\frac{1}{2}\right)}{1-\frac{1}{6}}+\tan ^{-1} x=\pi \end{array}

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