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Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 26

Answers (1)

Answer:

                \pi-2x

Hints:

You must know the rules of inverse trigonometric functions

Given:

              0<x<\frac{\pi}{2} then \sin^{-1}\left ( \cos x \right )+\cos^{-1}\left ( \sin x\right )

Solution:

                \sin^{-1}\left ( \cos x \right )+\cos^{-1}\left ( \sin x\right )

                \sin^{-1}\left ( \sin\left ( \frac{\pi}{2}-x \right ) \right )+\cos^{-1}\left ( \cos\left ( \frac{\pi}{2}-x \right )\right )                                           x=\sin\left ( \frac{\pi}{2}-x \right )]

                \frac{\pi}{2}-x+\frac{\pi}{2}-x

                \frac{2\pi}{2}-2x

                \pi-2x

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