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Name: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 57 maths textbook solution
Uploaded: Sat, 2021-08-07 15:52
Description: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 57 maths textbook solution

#R.D. Sharma
#Inverse Trigonometric Functions
#RD Sharma Vol. 1 Class 12
#School
#Maths
#CBSE 12 Class

#1.3
#3.1
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 57 maths textbook solution

Answers (1)

Answer: $\frac{5 \pi}{6}$

Given:

$2 \sec ^{-1} 2+\sin ^{-1}\left(\frac{1}{2}\right)$

Hint: Try to convert or find the values of

$\sin ^{-1}\left(\frac{1}{2}\right), \sec ^{-1}(2)$

Solution:

$\begin{aligned} 2 \sec ^{-1} 2+\sin ^{-1}\left(\frac{1}{2}\right) &=2 \sec ^{1}\left(\sec \frac{\pi}{3}\right)+\sin ^{-1}\left(\sin \frac{\pi}{6}\right) \\ &=2 \times \frac{\pi}{3}+\frac{\pi}{6} \\ &=\frac{5 \pi}{6} \end{aligned}$

Posted by

infoexpert22

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 57 maths textbook solution

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