Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 8 math

Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 8 math

Answers (1)

Answer: \pi

Given:

\cos ^{-1}\left(\cos \frac{2 \pi}{3}\right)+\sin ^{-1}\left(\sin \frac{2 \pi}{3}\right)                                     

Hint:

Range of  \sin \left(\frac{-\pi}{2}, \frac{\pi}{2}\right) ; \frac{\pi}{3} \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)

Range of    \cos [0, \pi], \frac{2 \pi}{3} \in(0, \pi)

Solution:

\begin{aligned} \cos ^{-1}\left(\cos \frac{2 x}{3}\right)+\sin ^{-1}\left(\sin \frac{2 x}{3}\right) &=\cos ^{-1}\left(\cos \frac{2 x}{3}\right)+\sin ^{-1}\left[\sin \left(\frac{2 x}{3}\right)\right] \\ &=\frac{2 \pi}{3}+\pi-\frac{2 \pi}{3} \\ &=\pi \end{aligned}

Posted by

infoexpert22

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

QR code in CBSE Class 12 maths paper redirects to 'rickroll' prank video; board says exam integrity intact
anam-khan

Iran-Israel Conflict: CBSE postpones Class 12 board exams 2026 till March 16 in Middle East
anam-khan

CBSE Class 12 Maths 2026 paper ‘moderate, balanced’ in difficulty; experts flag one out-of-syllabus question

Latest Question