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  • Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise Multiple Choice Questions Question 35 maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise Multiple Choice Questions Question 35 maths Textbook Solution.

Answers (1)

Answer: \frac{19}{8}

Try to solve \cos ^{-1}and \\tan ^{-1}function.

Given: \tan \left(\cos ^{-1}\left(\frac{3}{5}\right)+\tan ^{-1}\left(\frac{1}{4}\right)\right)

Solution:

\tan \left(\cos ^{-1}\left(\frac{3}{5}\right)+\tan ^{-1}\left(\frac{1}{4}\right)\right)_{=}^{\tan }\left(\tan ^{-1}\left(\frac{\sqrt{1-\frac{9}{25}}}{\frac{3}{5}}\right)+\tan ^{-1}\left(\frac{1}{4}\right)\right)

                                                               =\tan \left(\tan ^{-1}\left(\frac{\frac{4}{5}}{\frac{3}{5}}\right)+\tan ^{-1}\left(\frac{1}{4}\right)\right)

                                                                =\tan \left(\tan ^{-1} \frac{4}{3}+\tan ^{-1} \frac{1}{4}\right)

                                                                =\tan \left(\tan ^{-1} \frac{\frac{4}{3}+\frac{1}{4}}{1-\frac{1}{3}}\right)

                                                                

                                                               =  \frac{19}{8}  Alignment needs improvement

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