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  • Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 36 math

Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 36 math

Answers (1)

Answer:\frac{1}{2}

Given:

4 \sin ^{-1} x+\cos ^{-1} x=\pi

Hint:

\sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}

Solution:

\begin{array}{l} \therefore 4 \sin ^{-1} x+\cos ^{-1} x=\pi \\\\ 4 \sin ^{-1} x+\frac{\pi}{2}-\sin ^{-1} x=\pi \quad\left[\therefore \sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}\right] \\\\ 3 \sin ^{-1} x=\frac{\pi}{2} \\\\ \sin ^{-1} x=\frac{\pi}{6} \\\\ x=\sin \frac{\pi}{6} \\\\ x=\frac{1}{2} \end{array}

 

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