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Name: Provide solution for RD Sharma maths class 12 Chapter Inverse trigromtery functions exercise 3.8 question 1 sub question (I)
Uploaded: Thu, 2021-07-08 17:40
Description: Provide solution for RD Sharma maths class 12 Chapter Inverse trigromtery functions exercise 3.8 question 1 sub question (I)

#R.D. Sharma
#Maths
#RD Sharma Vol. 1 Class 12
#School
#Inverse Trigonometric Functions
#CBSE 12 Class

#1.3
#3.1
#3.2
#3.3
#3.4
#3.5
#3.6
#3.7
#3.8
#3.9
#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide solution for RD Sharma maths class 12 Chapter Inverse trigromtery functions exercise 3.8 question 1 sub question (I)

Answers (1)

$\frac{7}{25}$

Hint:

As we know that the value of $\sin \left(\sin ^{-1} x\right) \text { is } x \text { for } x \in[-1,1]$

Given:

We have,

$\sin \left(\sin ^{-1} \frac{7}{25}\right)$

Solution:

So here in the expression already present the form of $\sin \left(\sin ^{-1} x\right)$

$\sin \left(\sin ^{-1} \frac{7}{25}\right)=\frac{7}{25} \mid$

Posted by

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Provide solution for RD Sharma maths class 12 Chapter Inverse trigromtery functions exercise 3.8 question 1 sub question (I)

Answers (1)

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