Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • provide solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (viii)

provide solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise  3.7 question 3 sub question (viii)

Answers (1)

best_answer

Answer: 12-4\pi

Hint: The range of principal value of  \tan ^{-1} is \left [ -\frac{\pi }{2} ,\frac{\pi }{2}\right ]
Given:  \tan ^{-1}(\tan 12)

Explanation:

As        \tan ^{-1}(\tan x)=x \text { if } x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

But here x=12  which does not belongs to above range

            \begin{aligned} &\tan (2 n \pi-\theta)=-\tan (\theta) \\ &\tan (\theta-2 n \pi)=\tan \theta \end{aligned}

Here,     n=2

            \tan (12-4 \pi)=\tan (12)

Now,     12-4 \pi \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

Hence,  \tan ^{-1}(\tan 12)=12-4 \pi

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question