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Name: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 16 Maths Textbook Solution.
Uploaded: Thu, 2021-08-05 14:44
Description: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 16 Maths Textbook Solution.

#Maths
#Inverse Trigonometric Functions
#R.D. Sharma
#RD Sharma Vol. 1 Class 12
#CBSE 12 Class
#School

#1.3
#3.1
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#3.11
#3.12
#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 16 Maths Textbook Solution.

Answers (1)

Answer: None of these

Hint: $\tan ^{-1} x+\tan ^{-1} y=\tan ^{-1}\left(\frac{x+y}{1-x y}\right)$

Given: $\tan ^{-1} \frac{1}{11}+\tan ^{-1} \frac{2}{11}=?$

Solution:

$\tan ^{-1} \frac{1}{11}+\tan ^{-1} \frac{2}{11}=\left(\frac{\frac{1}{11}+\frac{2}{11}}{1-\left(\frac{1}{11}\right)\left(\frac{2}{11}\right)}\right)$

$=\tan ^{-1}\left(\frac{\frac{3}{11}}{\frac{119}{121}}\right)$

$\begin{aligned} &=\tan ^{-1}\left(\frac{33}{119}\right) \\ &=0.27 \end{aligned}$

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 16 Maths Textbook Solution.

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