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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 12 math

Answers (1)

Answer:\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

Given:

Range of  \tan ^{-1} x

Hint: Range of  \tan  function should be all real number.

Solution:

                 \tan ^{-1} x=\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

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