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need solution for RD Sharma maths class 12 chapter Inverse Trignometric Functions exercise 3.7 question 3 sub question (i)

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Answer:  \\ \\ \frac{\pi}{3} 

Hint: The principal value branch of function \cos ^{-1} is \left [ 0,\pi \right ]
Given: \tan ^{-1}\left(\tan \frac{\pi}{3}\right)

Explanation:

As            \tan ^{-1}(\tan x)=x \text { if } x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

By applying this situation

we get

            \tan ^{-1}\left(\tan \frac{\pi}{3}\right)=\frac{\pi}{3}

Hence, \tan ^{-1}\left(\tan \frac{\pi}{3}\right) \text { is } \frac{\pi}{3}

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