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Name: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise MCQs Question 19 Maths Textbook Solution.
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Description: Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise MCQs Question 19 Maths Textbook Solution.

#CBSE 12 Class
#School
#RD Sharma Vol. 1 Class 12
#Maths
#Inverse Trigonometric Functions
#R.D. Sharma

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#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise MCQs Question 19 Maths Textbook Solution.

Answers (1)

Answer: $\frac{-\pi}{10}$

Hint: Just separate cos function into two parts.

Given: $\sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)$

We have to compute x.

Solution:

$\sin ^{-1}\left(\cos \frac{33 \pi}{5}\right)_{=} \sin ^{-1}\left\{\cos \left(6 \pi+\frac{3 \pi}{5}\right)\right\}$

$=\sin ^{-1}\left\{\sin \left(\frac{\pi}{2}-\frac{3 \pi}{5}\right)\right\}$

$\begin{aligned} &=\frac{\pi}{2}-\frac{3 \pi}{5} \\ &=\frac{-\pi}{10} \end{aligned}$

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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise MCQs Question 19 Maths Textbook Solution.

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