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  • Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 16 math

Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 16 math

Answers (1)

Answer: 70 \degree

Given:

\sin ^{-1}\left(\sin 1550^{\circ}\right)

Hint:

\sin ^{-1}(\sin x)=x

Solution:

We, know that

\sin ^{-1}(\sin x)=x

Now,          

\begin{aligned} \sin ^{-1}\left(\sin 1550^{\circ}\right) &=\sin ^{-1}\left\{\sin \left(1620^{\circ}-1550^{\circ}\right)\right\} \\ &=\sin ^{-1}\left(\sin 70^{\circ}\right) \\ &=70^{\circ} \end{aligned}

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