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Explain solution for RD Sharma class class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 48 math

Answers (1)

Answer:  \frac{2 \pi}{3}

Given: \cos ^{-1}\left[\cos \left(4 \pi+\frac{2 \pi}{3}\right)\right]

Hint: Try to solve \cos \left(\frac{14 \pi}{3}\right)  function.

Solution:

\cos ^{-1}\left(\cos \frac{14 \pi}{3}\right)=\cos ^{-1}\left[\cos \left(4 \pi+\frac{2 \pi}{3}\right)\right]

                                          \begin{array}{l} =\cos ^{-1}\left(\cos \frac{2 \pi}{3}\right) \\\\ =\frac{2 \pi}{3} \end{array}

 

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