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Need solution for RD Sharma maths class 12 chapter 3 Inverse Trigonometric Functions exercise  Very short answer question 59 math

Answers (1)

Answer:  \frac{\pi}{6}

Given:

\cos ^{-1}\left(\cos ^{-1} \frac{3 \pi}{6}\right)

Hint: To solve \cos  function we can get the solution.

Solution:       

\begin{aligned} \cos ^{-1}\left(\cos \frac{13 \pi}{6}\right) &=\cos ^{-1}\left[\cos \left(2 \pi+\frac{\pi}{6}\right)\right] \\ &=\cos ^{-1}\left(\cos \left(\frac{\pi}{6}\right)\right) \\ &=\frac{\pi}{6} \end{aligned}

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