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  • Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46

Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46

Answers (1)

Answer: \frac{2 \pi}{5}

Given: \sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)                  

Hint: Try to solve \left(\sin \frac{3 \pi}{5}\right)  first.

Solution:

\begin{aligned} \sin ^{-1}\left(\sin \frac{3 \pi}{5}\right) &=\sin ^{-1}\left[\sin \left(\pi-\frac{2 \pi}{5}\right)\right] \\ &=\sin ^{-1}\left(\sin \frac{2 \pi}{5}\right) \\ &=\frac{2 \pi}{5} \end{aligned}

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