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Name: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46
Uploaded: Sat, 2021-08-07 08:01
Description: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46

#Inverse Trigonometric Functions
#Maths
#R.D. Sharma
#School
#CBSE 12 Class
#RD Sharma Vol. 1 Class 12

#1.3
#3.1
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46

Answers (1)

Answer: $\frac{2 \pi}{5}$

Given: $\sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)$

Hint: Try to solve $\left(\sin \frac{3 \pi}{5}\right)$ first.

Solution:

$\begin{aligned} \sin ^{-1}\left(\sin \frac{3 \pi}{5}\right) &=\sin ^{-1}\left[\sin \left(\pi-\frac{2 \pi}{5}\right)\right] \\ &=\sin ^{-1}\left(\sin \frac{2 \pi}{5}\right) \\ &=\frac{2 \pi}{5} \end{aligned}$

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 46

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