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Name: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 41 maths textbook solution
Uploaded: Fri, 2021-08-06 22:49
Description: Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 41 maths textbook solution

#R.D. Sharma
#RD Sharma Vol. 1 Class 12
#Maths
#Inverse Trigonometric Functions
#School
#CBSE 12 Class

#1.3
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 41 maths textbook solution

Answers (1)

Answer: $\frac{5}{12}$

Given:

$\tan \left(2 \tan ^{-1} \frac{1}{5}\right)$

Hint:

Use formula

Solution:

$\begin{aligned} \tan \left(2 \tan ^{-1} \frac{1}{5}\right) &=\tan \left(\tan ^{-1} \frac{2 \times\left(\frac{1}{5}\right)}{1-\left(\frac{1}{5}\right)^{2}}\right) \\\\ &=\tan \left(\tan ^{-1} \frac{\frac{2}{5}}{\frac{24}{25}}\right) \\\\ &=\frac{5}{12} \end{aligned}$

Posted by

infoexpert22

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Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 41 maths textbook solution

Answers (1)

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