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Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise MCQs Question 32 maths Textbook Solution.

Answers (1)

Answer: 0.96

Hint: Try to separate the tan-1 function and then move onto the sin function.

Given: \sin \left(2\left(\tan ^{-1} 0.75\right)\right)


\sin \left(2\left(\tan ^{-1} 0.75\right)\right)=\sin \left(2 \tan ^{-1} 0.75\right)

                                        =\sin \left(\sin ^{-1} \frac{2(0.75)}{1+(0.75)^{2}}\right)

                                        =\sin \left(\sin ^{-1} 0.96\right)

                                        =0.96 Alignment needs improvement

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