Get Answers to all your Questions

header-bg qa

Need solution for RD Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Excercise Fill in the Blanks Question 35

Answers (1)

Answer:

              (-\infty,-1]\cup [1,\infty)

Hints:

You must have known about the principal values and range of inverse trigonometric function

Given:

                y=\sec^{-1}x

Solution:

 y=\sec^{-1}x

The range of principal value branch of y=\sec^{-1}x

Principal value branch of y=\sec^{-1}x is\left [ 0,\pi \right ]-\left \{ \frac{\pi}{2} \right \}

And the range is in \left ( 1,\infty \right ) it is increasing and \left (-\infty,-1 \right ) it is increasing

The function does not have any inflection points

\thereforeThe range of y=\sec^{-1}x is (-\infty,-1]\cup [1,\infty)

 

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads