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Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise Multiple Choice Questions Question 33 maths Textbook Solution.

Answers (1)

Answer: 4 \tan ^{-1} x

Hint \sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)=2 \tan ^{-1} x

Given: \mathrm{x}>1,then 2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)

Solution:

2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^{2}}\right)=2 \tan ^{-1} x+2 \tan ^{-1} x

                                                        =4 \tan ^{-1} x Alignment needs improvement

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