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Explain Solution R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Function Exercise MCQs Question 38 maths Textbook Solution.

Answers (1)

Answer: \frac{\sqrt{1-x^{2}}}{x}

Hint: Try to solve \sin ^{-1} function

Given: \cot \left(\sin ^{-1} x\right)

Solution:

Let, \sin ^{-1} x=\theta

       \begin{aligned} &\sin \theta=x \\ &\csc \theta=\frac{1}{x} \Rightarrow \csc ^{2} \theta=\frac{1}{x^{2}} \\ &1+\cot ^{2} \theta=\frac{1}{x^{2}} \\ &\cot \theta=\frac{\sqrt{1-x^{2}}}{x} \end{aligned}

 

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