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Provide Solution For R.D.Sharma Maths Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 20 Maths Textbook Solution.

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Hint: Separate cos function into simple form.

Given: \cos ^{-1}\left(\cos \frac{5 \pi}{3}\right)+\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)


\cos ^{-1}\left(\cos \frac{5 \pi}{3}\right)+\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)=\cos ^{-1}\left(\cos \left(2 \pi-\frac{\pi}{3}\right)\right)+\sin ^{-1}\left(\sin \left(2 \pi-\frac{\pi}{3}\right)\right)

                                                                  =\cos ^{-1}\left(\cos \left(\frac{\pi}{3}\right)\right)+\sin ^{-1}\left(\sin \left(\frac{\pi}{3}\right)\right)

                                                                    \begin{aligned} &=\frac{\pi}{3}-\frac{\pi}{3} \\ &=0 \end{aligned}

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