Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.10 Question 9 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter Inverse Trigonometric Function Exercise 3.10 Question 9 Maths Textbook Solution.

Answers (1)

Answer: \sqrt{3}
Hint: Use \tan^{-1}x + \cot^{-1}x= \frac{\pi }{2}
Given: \tan^{-1}x + 2\cot^{-1}x= \frac{2\pi }{3}
Here, we have to compute x.
Solution:
We have, \tan^{-1}x + \cot^{-1}x= \frac{\pi }{2}
Therefore,
\! \! \! \! \! \! \! \! \Rightarrow \frac{\pi }{2} - \tan^{-1}x = \cot ^{-1}x\\ \Rightarrow \tan^{-1}x + 2 \cot^{-1}x =\frac{2\pi }{3}\\ \Rightarrow \tan^{-1}x + 2 (\frac{\pi }{2} - \tan^{-1}x ) = \frac{2\pi }{3}\\ \Rightarrow \pi - \tan^{-1}x = \frac{2\pi }{3}\\ \Rightarrow \pi - \frac{2\pi }{3} = \tan^{-1}x\\ \Rightarrow 3\pi - \frac{2\pi }{3} = \tan^{-1}x\\ \Rightarrow \frac{\pi }{3} = \tan^{-1}x\\ \Rightarrow x = \tan \frac{\pi }{3}\\\Rightarrow x = \sqrt{3}
Concept: Properties of inverse trigonometric functions.
Note: Derive value of basic Trigonometric functions.

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question