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  • Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 26

Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 26

Answers (1)

Answer: 1

Given: \sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right\}

Hint: Try to solve the \sin ^{-1}  function.

Solution:        

\begin{aligned} \sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right\} &=\sin \left\{\frac{\pi}{3}-\left(\frac{-\pi}{6}\right)\right\} \\ &=\sin \left\{\frac{\pi}{3}+\frac{\pi}{6}\right\}=\sin \frac{\pi}{2} \\ &=1 \end{aligned}

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