Get Answers to all your Questions

header-bg qa

Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 26

Answers (1)

Answer: 1

Given: \sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right\}

Hint: Try to solve the \sin ^{-1}  function.

Solution:        

\begin{aligned} \sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right\} &=\sin \left\{\frac{\pi}{3}-\left(\frac{-\pi}{6}\right)\right\} \\ &=\sin \left\{\frac{\pi}{3}+\frac{\pi}{6}\right\}=\sin \frac{\pi}{2} \\ &=1 \end{aligned}

Posted by

infoexpert22

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads