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  • Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 25 maths textbook solution

Please solve RD Sharma class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 25 maths textbook solution

Answers (1)

Answer: \frac{7 \pi}{18}

Given: \sin ^{-1}\left(\cos \frac{\pi}{9}\right)

Hint: \cos x=\sin \left(\frac{\pi}{2}-x\right)

Solution:             

\begin{aligned} \sin ^{-1}\left(\cos \frac{\pi}{9}\right) &=\sin ^{-1}\left\{\sin \left(\frac{\pi}{2}-\frac{\pi}{9}\right)\right\} \\ &=\sin ^{-1}\left\{\sin \left(\frac{7 \pi}{18}\right)\right\} \\ &=\frac{7 \pi}{18} \end{aligned}

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