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Name: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 34
Uploaded: Fri, 2021-08-06 21:48
Description: Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 34

#R.D. Sharma
#CBSE 12 Class
#Inverse Trigonometric Functions
#Maths
#RD Sharma Vol. 1 Class 12
#School

#1.3
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#9.12
#3.10
#Fill in the blanks
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#18.1
#3.14
#3.13

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 34

Answers (1)

Answer:

$x=\frac{1}{3}$

Given: $\sin ^{-1}\left(\frac{1}{3}\right)+\cos ^{-1} x=\frac{\pi}{2}$

Hint:

$\sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}$

Solution:

\ $\begin{array}{ll} \sin ^{-1}\left(\frac{1}{3}\right)+\cos ^{-1} x=\frac{\pi}{2} \\\\ \sin ^{-1}\left(\frac{1}{3}\right)=\frac{\pi}{2}-\cos ^{-1} x \\\\ \sin ^{-1}\left(\frac{1}{3}\right)=\sin ^{-1} x \\\\ \end{array}$

$x=\frac{1}{2}$

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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 34

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