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Provide solution for RD Sharma math class 12 chapter 3 Inverse Trigonometric Functions exercise Very short answer question 34

Answers (1)

Answer:

x=\frac{1}{3}

Given: \sin ^{-1}\left(\frac{1}{3}\right)+\cos ^{-1} x=\frac{\pi}{2}

Hint:

\sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}

Solution:         

\\begin{array}{ll} \sin ^{-1}\left(\frac{1}{3}\right)+\cos ^{-1} x=\frac{\pi}{2} \\\\ \sin ^{-1}\left(\frac{1}{3}\right)=\frac{\pi}{2}-\cos ^{-1} x \\\\ \sin ^{-1}\left(\frac{1}{3}\right)=\sin ^{-1} x \\\\ \end{array}

                    x=\frac{1}{2}

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