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Please Solve R.D.Sharma Class 12 Chapter 3 Inverse Trigonometric Functions Exercise Multiple Choice Questions Question 24 Maths Textbbok Solution.

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Answer: \frac{\sqrt{3}}{2}

Hint: \sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}

Solution:Given ,   4\cos^{-1}x+\sin^{-1}x=\pi

\sin ^{-1} x+\cos ^{-1} x=\frac{\pi}{2}

4 \cos ^{-1} x+\frac{\pi}{2}-\cos ^{-1} x=\pi

3 \cos ^{-1} x=\pi-\frac{\pi}{2}

\cos ^{-1} x=\frac{\pi}{6}

\mathrm{x}=\frac{\sqrt{3}}{2}

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